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C++ Tutorial - Linked List Examples - 2012
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JangHeung

Linked Lists

A linked list is a basic data structure where each item contains the information that we need to get to the next item. The main advantage of linked lists over arrays is that the links provide us with the capability to rearrange the item efficiently. This flexibility is gained at the expense of quick access to any arbitrary item in the list, because the only way to access to an item in the list is to follow links from the beginning.



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Linked List Examples

The following examples are for the linked list. Inside each example, we have several operations:

  • Reversing the linked list (#1, #3, #4)
  • Copying the linked list(#1)
  • Detecting circular (loop) linked list(#5)
  • Comparing the two linked list(#1)
  • Deleting the linked list(#1)
  • Adding, deleting, inserting, and searching a node (all examples)
  • Stack implementation with linked list (#6, #7)
  • Finding intersection and union of two lists (#8)




  • Example 1
    When the head of the list is not a global pointer.
  • Example 2 and Example 3
    When the head of the list is a global pointer.
    There are some implementation differences between these two examples.
  • Example 4
    Used class & structure in that class.
  • Example 5A
    Detecting circular (loop) linked list.
  • Example 5B
    Detecting circular (loop) linked list (Generic Class with Template).
  • Example 6
    Stack with linked list data structure.
  • Example 7
    Class Stack with linked list data structure.
  • Example 8
    Queue with linked list data structure.
  • Example 9
    Finding intersection and union of two linked lists.
  • Example 10
    Generic linked lists.

Also, there is another set of linked list quiz.



Example 1
#include <iostream>

using namespace std;

struct Node {
	int data;
	Node* next;
};

// only for the 1st Node
void initNode(struct Node *head,int n){
	head->data = n;
	head->next =NULL;
}

// apending
void addNode(struct Node *head, int n) {
	Node *newNode = new Node;
	newNode->data = n;
	newNode->next = NULL;

	Node *cur = head;
	while(cur) {
		if(cur->next == NULL) {
			cur->next = newNode;
			return;
		}
		cur = cur->next;
	}
}

void insertFront(struct Node **head, int n) {
	Node *newNode = new Node;
	newNode->data = n;
	newNode->next = *head;
	*head = newNode;
}

struct Node *searchNode(struct Node *head, int n) {
	Node *cur = head;
	while(cur) {
		if(cur->data == n) return cur;
		cur = cur->next;
	}
	cout << "No Node " << n << " in list.\n";
}

bool deleteNode(struct Node **head, Node *ptrDel) {
	Node *cur = *head;
	if(ptrDel == *head) {
		*head = cur->next;
		delete ptrDel;
		return true;
	}
	
	while(cur) {
		if(cur->next == ptrDel) {
			cur->next = ptrDel->next;
			delete ptrDel;
			return true;
		}
		cur = cur->next;
	}
	return false;
}

/* reverse the list */
struct Node* reverse(struct Node** List) 
{
	Node *parent = *List;
	Node *me = parent->next;
	Node *child = me->next;

	/* make parent as tail */
	parent->next = NULL;
	while(child) {
		me->next = parent;
		parent = me;
		me = child;
		child = child->next;
	}
	me->next = parent;
	*List = me;
	return *List;
}

/* Creating a copy of a linked list */
void copyLinkedList(struct Node *node, struct Node **pNew)
{
	if(node != NULL) {
		*pNew = new Node;
		(*pNew)->data = node->data;
		(*pNew)->next = NULL;
		copyLinkedList(node->next, &((*pNew)->next));
	}
}

/* Compare two linked list */
/* return value: same(1), different(0) */
int compareLinkedList(struct Node *node1, struct Node *node2)
{
	static int flag;

	/* both lists are NULL */
	if(node1 == NULL && node2 == NULL) {
		flag = 1;
	}
	else {
		if(node1 == NULL || node2 == NULL) 
			flag = 0;
		else if(node1->data != node2->data) 
			flag = 0;
		else
			compareLinkedList(node1->next, node2->next);
	}

	return flag;
}

void deleteLinkedList(struct Node **node)
{
	struct Node *tmpNode;
	while(*node) {
		tmpNode = *node;
		*node = tmpNode->next;
		delete tmpNode;
	}
}

void display(struct Node *head) {
	Node *list = head;
	while(list) {
		cout << list->data << " ";
		list = list->next;
	}
	cout << endl;
	cout << endl;
}

int main() 
{
	struct Node *newHead;
	struct Node *head = new Node;
	
	initNode(head,10);
	display(head);

	addNode(head,20);
	display(head);

	addNode(head,30);
	display(head);

	addNode(head,35);
	display(head);

	addNode(head,40);
	display(head);

	insertFront(&head,5);
	display(head);

	int numDel = 5;
	Node *ptrDelete = searchNode(head,numDel);
	if(deleteNode(&head,ptrDelete)) 
		cout << "Node "<< numDel << " deleted!\n";
	display(head);

	cout << "The list is reversed\n";
	reverse(&head);
	display(head);

	cout << "The list is copied\n";
	copyLinkedList(head,&newHead);
	display(newHead);

	cout << "Comparing the two lists...\n";
	cout << "Are the two lists same?\n";
	if(compareLinkedList(head,newHead)) 
		cout << "Yes, they are same!\n";
	else
		cout << "No, they are different!\n";
	cout << endl;

	numDel = 35;
	ptrDelete = searchNode(newHead,numDel);
	if(deleteNode(&newHead,ptrDelete)) {
		cout << "Node "<< numDel << " deleted!\n";
		cout << "The new list after the delete is\n";
		display(newHead);
	}
	cout << "Comparing the two lists again...\n";
	cout << "Are the two lists same?\n";
	if(compareLinkedList(head,newHead)) 
		cout << "Yes, they are same!\n";
	else
		cout << "No, they are different!\n";
    
	cout << endl;
	cout << "Deleting the copied list\n";
	deleteLinkedList(&newHead);
	display(newHead);
	return 0;
}

Output from the run:

10

10 20

10 20 30

10 20 30 35

10 20 30 35 40

5 10 20 30 35 40

Node 5 deleted!
10 20 30 35 40

The list is reversed
40 35 30 20 10

The list is copied
40 35 30 20 10

Comparing the two lists...
Are the two lists same?
Yes, they are same!

Node 35 deleted!
The new list after the delete is
40 30 20 10

Comparing the two lists again...
Are the two lists same?
No, they are different!

Deleting the copied list




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Example 2
#include <iostream>

using namespace std;

struct node {
	int data;
	struct node * next;
};

node *head = NULL;

// returning the pointer to the element 
// whose data is less than or equal to input data
struct node *searchNode(int n) {
	if(head == NULL) return head;
	node *cur = head;
	node *prev = head;
	while(cur) {
		if(cur->data == n) return cur;
		if(cur->data > n) return prev;
		prev = cur;
		cur = cur->next;
	}
}

// returning the pointer to the element 
// whose data is equal to input data
struct node *searchNode2(int n) {
	if(head == NULL) return head;
	node *cur = head;
	node *prev = head;
	while(cur) {
		if(cur->data == n) return cur;
		prev = cur;
		cur = cur->next;
	}
	return cur;
}

void addNode(int n) {
	node *newNode = new node;
	newNode->data = n;
	newNode->next = NULL;

	if(head == NULL) {
		head = newNode;
		return;
	}
	node *cur = head;
	while(cur) {
		if(cur->next == NULL) {
			cur->next = newNode;
			return;
		}
		cur = cur->next;
	}
}

void insertNode(int n) {
	node *ptr = searchNode(n);
	node *newNode = new node;
	newNode->data = n;
	node *cur = head;
	while(cur) {
		if(cur == ptr ) {
			newNode->next = cur->next;
			cur->next = newNode;
			return;
		}
		cur = cur->next;
	}
}

void deleteNode(int n) {
	node *ptr = searchNode(n);
	if(ptr == NULL) 
		cout << "No node with data = " << n << endl;
	if(ptr == head) {
		head = ptr->next;
		return;
	}
	node *cur = head;
	node *prev = head;

	while(cur) {
		if(cur == ptr) {
			prev->next = cur->next;
			return;
		}
		prev = cur;
		cur = cur->next;
	}
}

void display() {
	struct node *list = head;
	while(list) {
		cout << list->data <<" ";
		list = list->next;
	}
	cout << endl;
}

int main()
{
	addNode(10);
        display();
	addNode(20);
	display();
	addNode(40);
	display();
	addNode(50);
	display();
	insertNode(30);
	display();
	deleteNode(40);
	display();
	return 0;
}



Example 3

// linked list example - using struct
#include <iostream>
#include <cstring>

using namespace std;

struct node * initNode( char *, int );
void displayNode( struct node * );
void displayList( struct node * );
void addNode( struct node * );
struct node * searchName( struct node *, char * );
void deleteNode( struct node * );
void insertNode( struct node * );
void deleteList( struct node * );

struct node {
   char name[20];
   int  id;
   struct node *next;
};

struct node *head = (struct node *) NULL;
struct node *tail = (struct node *) NULL;

// allocates memory for the node
// assign values to the member of the structure
struct node * initNode( char *name, int id )
{
   struct node *ptr = new node;

   // error? then just return
   if( ptr == NULL )                        
       return static_cast<struct node *>(NULL);       
   	// assign it 
	// then return pointer to ne node
   else {                                   
       strcpy( ptr->name, name );           
       ptr->id = id;                        
       return ptr;                   
   }
}

// adding to the end of list
void addNode( struct node *newnode )   
{
	// if there is no node, put it to head
	if( head == NULL ) {           
       head = newnode;                          
       tail = newnode;
	}

	// link in the new_node to the tail of the list
	// then mark the next field as the end of the list
	// adjust tail to point to the last node

	tail->next = newnode;         
	newnode->next = NULL;        
	tail = newnode;              
}
                                                            
void insertNode( struct node *newnode )
{
   struct node *temp, *prev;                 

   if( head == NULL ) {                     // if an empty list,  
       head = newnode;                      // set 'head' to it  
       tail = newnode;
       head->next = NULL;                   // set end of list to NULL 
       return;                             
   }

   temp = head;                             // start at beginning of list
					    // while currentname < newname 
   while( strcmp( temp->name, newnode->name) < 0 ) {
					    // to be inserted then 
          temp = temp->next;                // goto the next node in list
          if( temp == NULL )                // don't go past end of list  
              break;
   }
					    // set previous node before we insert  
					    // first check to see if it's inserting   
   if( temp == head ) {		    	    // before the first node 
      newnode->next = head;                 // link next field to original list  
      head = newnode;                       // head adjusted to new node
   }
   else {				    // it's not the first node
      prev = head;			    // start of the list,
      while( prev->next != temp ) {	    // will cycle to node before temp
          prev = prev->next;
      }
      prev->next = newnode;		    // insert node between prev and next 
      newnode->next = temp;
      if( tail == prev )		    // if the new node is inserted at the 
         tail = newnode;		    // end of the list the adjust 'end' 
   }
}

struct node * searchName( struct node *ptr, char *name )
{
    while( strcmp( name, ptr->name ) != 0 ) {   
       ptr = ptr->next;                          
       if( ptr == NULL )                         
          break;                                  
    }
    return ptr;                                  
}

struct node* searchId(struct node* ptr, int id) {
    while( id != ptr->id ) {    
       ptr = ptr->next;                          
       if( ptr == NULL )                          
          break;                                  
    }
    return ptr; 	
}

void reverse() {
	// we need at least two nodes for the reverse to have any effect
	if(head == NULL || head->next == NULL) return;

	// Starting 2nd list as 'me' and 'head' is now 'me->next'
	// and 'head->next' is pointing to NULL
	// So, the 3rd list is now 'child' of 'me'
	node *parent = head;
	node *me = head->next;
	node *child = me->next;

	// convert head to tail
	parent->next = NULL;
	
	while(child != NULL){
		me->next = parent;
		parent = me;
		me = child;
		child = child->next;
	}
	// when me reached the tail
	// me becomes head
	head = me;
	// the head is now pointing to the 2nd last node
	head->next = parent;
}

void deleteNode( struct node *ptr )
{
  struct node *temp, *prev;
   temp = ptr;    // node to be deleted 
   prev = head;   // start of the list, will cycle to node before temp    

   if( temp == prev ) {                    // deleting first node?  
       head = head->next;                  // moves head to next node     
       if( tail == temp )                  // is it end, only one node?   
          tail = tail->next;               // adjust end as well          
       delete temp ;                       // free up space 
   }
   else {                                  // if not the first node, then 
       while( prev->next != temp ) {       // move prev to the node before
           prev = prev->next;              // the one to be deleted       
       }
       prev->next = temp->next;            // link previous node to next  
       if( tail == temp )                  // if this was the end node,   
           tail = prev;                    // then reset the end pointer  
      delete temp;                         // free up space
   }
}

void deleteList( struct node *ptr )
{
   struct node *temp;

   if( head == NULL ) return;   	// don't try to delete an empty list      

   if( ptr == head ) {			// if we are deleting the entire list    
       head = NULL;			// then reset head and    
       tail = NULL;			// end to empty                                     
   }
   else {
       temp = head;			// if it's not the entire list, readjust end   
       while( temp->next != ptr )       // locate previous node to ptr   
           temp = temp->next;
       tail = temp;                     // set end to node before ptr   
   }

   while( ptr != NULL ) {		// while there are still nodes to delete      
      temp = ptr->next;			// record address of next node                 
      delete ptr;			// free this node                             
      ptr = temp;			// point to next node to be deleted           
   }
}


void displayNode( struct node *ptr ) {
	cout << ptr->id << ": " << ptr->name << endl;
}


void displayList( struct node *ptr ) {
   while( ptr != NULL )           {
      displayNode( ptr );           
      ptr = ptr->next;            
   }
}



#include <iostream>
using namespace std;

int main()
{
   	char* name;
   	int id, ch = 1;
   	struct node *ptr;

	// add
	ptr = initNode( "s1", 1 );
	addNode(ptr);
	ptr = initNode( "s2", 2 );
	addNode(ptr);
	ptr = initNode( "s3", 3 );
	addNode(ptr);
	ptr = initNode( "s4", 4 );
	addNode(ptr);
	ptr = initNode( "s5", 5 );
	addNode(ptr); 
	displayList(head);

	// delete
	name = "s2";
	ptr = searchName(head, name );
	if( ptr == NULL ) {
		cout << "\nName: " << name << " not found" << endl;
	}
	else {
		cout << "\nDeleting a node ...  ";
	    displayNode(ptr);
		deleteNode( ptr );
	}
	displayList(head);

	// insert
	name = "s2";
	id = 2;
	ptr = initNode( name, id );
	insertNode( ptr );
	cout << "\nInserting a node ...  ";
	displayNode(ptr);
	displayList(head);

	// reverse
	cout << "\nReversing the list ...  \n";
	reverse();
	displayList(head);

	// delete
	cout << "\nIn the end, deleting the list ...  \n";
	deleteList(head);
	displayList(head);
	return 0;
}


Example 4
// linked list example - using struct inside a class
 
#include <iostream>
#include <string>
using namespace std;

class list
{
public:
	struct node {
		int id;
		string name;
		struct node *next;
	} *head, *tail, *ptr;	

	list():head(NULL),tail(NULL){}	// constructor	
	~list();			// destructor

	struct list::node* searchName(struct list::node*, string);	
	struct list::node* searchId(struct list::node*, int);
	struct list::node* initNode(string, int);

	void reverse();
	void addNode( struct list::node*);
	void insertNode( struct list::node*);
	void deleteNode( struct list::node*);
	void deleteList( struct list::node*);
	void displayList( struct list::node*)const ;
 	void displayNode( struct list::node*) const;	
};

list::~list() {
	node *current,*temp;
	current = head;
	temp = head;
	while(current != NULL) {
		current = current->next;
		delete temp;
		temp = current;
	}
}

struct list::node* list::initNode(string s, int i) {
	struct node *ptr = new node;
 
	// error? then just return
	if( ptr == NULL )                         
		return static_cast<struct node *>(NULL);  
	// assign it 
	// then return pointer to ne node
	else {  
		ptr->name = s ;  
		ptr->id = i;                        
		return ptr;                         
	}
}

// adding to the end of list  
void list::addNode( struct node *newNode )  {
	// if there is no node, put it to head
	if( head == NULL ) {
		head = newNode;  
		tail = newNode;
	}
   
	// link in the new_node to the tail of the list
	// then mark the next field as the end of the list
	// adjust tail to point to the last node

	tail->next = newNode;       
	newNode->next = NULL;       
	tail = newNode;               
}

void list::insertNode( struct node *newnode ) {
   struct node *temp, *prev;                

   if( head == NULL ) {                     // if an empty list,         
       head = newnode;                      // set 'head' to it         
       tail = newnode;
       head->next = NULL;                   // set end of list to NULL     
       return;                                             
   }

   temp = head;                             // start at beginning of list 
					    // while currentname < newname 
   while( temp->name < newnode->name) {	    // to be inserted then 
          temp = temp->next;                // goto the next node in list  
          if( temp == NULL )                // don't go past end of list    
              break;
   }							 
					    // set previous node before we insert  
					    // first check to see if it's inserting         
   if( temp == head ) {		    	    // before the first node 
      newnode->next = head;                 // link next field to original list    
      head = newnode;                       // head adjusted to new node          
   }
   else {				    // it's not the first node
      prev = head;		    	    // start of the list, 
      while( prev->next != temp ) {	
          prev = prev->next;	    	    // will cycle to node before temp 
      }
      prev->next = newnode;                 // insert node between prev and next   
      newnode->next = temp;
      if( tail == prev )		    // if the new node is inserted at the  
         tail = newnode;		    // end of the list the adjust 'end'    
   }
}

struct list::node* list::searchName(struct node* ptr, string name) {
    while( name != ptr->name ) {    
       ptr = ptr->next;                          
       if( ptr == NULL )                          
          break;                                  
    }
    return ptr; 	
}

struct list::node* list::searchId(struct node* ptr, int id) {
    while( id != ptr->id ) {    
       ptr = ptr->next;                          
       if( ptr == NULL )                          
          break;                                  
    }
    return ptr; 	
}

void list::reverse() {
	// we need at least two nodes for the reverse to have any effect
	if(head == NULL || head->next == NULL) return;

	// Starting 2nd list as 'me' and 'head' is now 'me->next'
	// and 'head->next' is pointing to NULL
	// So, the 3rd list is now 'child' of 'me'
	node *parent = head;
	node *me = head->next;
	node *child = me->next;

	// convert head to tail
	head->next = NULL;

	// reverse pointer direction
	me->next = head;
	
	while(child != NULL){
		me->next = parent;
		parent = me;
		me = child;
		child = child->next;
	}
	// when me reached the tail
	// me becomes head
	head = me;
	// the head is now pointing to the 2nd last node
	head->next = parent;
}
 

void list::deleteNode( struct list::node *ptr )
{
  struct node *temp, *prev;
   temp = ptr;    // node to be deleted 
   prev = head;   // start of the list, will cycle to node before temp    

   if( temp == prev ) {                    // deleting first node?  
       head = head->next;                  // moves head to next node     
       if( tail == temp )                  // is it end, only one node?   
          tail = tail->next;               // adjust end as well          
       delete temp ;                       // free up space 
   }
   else {                                  // if not the first node, then 
       while( prev->next != temp ) {       // move prev to the node before
           prev = prev->next;              // the one to be deleted       
       }
       prev->next = temp->next;            // link previous node to next  
       if( tail == temp )                  // if this was the end node,   
           tail = prev;                    // then reset the end pointer  
      delete temp;                         // free up space
   }
}

void list::deleteList( struct node *ptr )
{
   struct node *temp;

   if( head == NULL ) return;   	// don't try to delete an empty list      

   if( ptr == head ) {			// if we are deleting the entire list    
       head = NULL;			// then reset head and    
       tail = NULL;			// end to empty                                     
   }
   else {
       temp = head;			// if it's not the entire list, readjust end   
       while( temp->next != ptr )       // locate previous node to ptr   
           temp = temp->next;
       tail = temp;                     // set end to node before ptr   
   }

   while( ptr != NULL ) {		// whilst there are still nodes to delete      
      temp = ptr->next;			// record address of next node                 
      delete ptr;			// free this node                             
      ptr = temp;			// point to next node to be deleted           
   }
}

void list::displayNode( struct list::node *ptr ) const
{
	cout << ptr->id << ": " << ptr->name << endl;
}

void list::displayList( struct list::node *ptr ) const
{
	if(!ptr) cout << "Nothing to display" << endl;
	while(ptr) {
		displayNode(ptr);
		ptr = ptr->next;
	}
}

int main()
{
	int id;
	string name;
 	list myList;
	list::node* ptr;

	// add
	ptr = myList.initNode( "s1", 1 );
	myList.addNode(ptr);
	ptr = myList.initNode( "s2", 2 );
	myList.addNode(ptr);
	ptr = myList.initNode( "s3", 3 );
	myList.addNode(ptr);
	ptr = myList.initNode( "s4", 4 );
	myList.addNode(ptr);
	ptr = myList.initNode( "s5", 5 );
	myList.addNode(ptr); 
	myList.displayList(myList.head);

	// delete
	name = "s2";
	ptr = myList.searchName( myList.head, name );
	if( ptr == NULL ) {
		cout << "\nName: " << name << " not found" << endl;
	}
	else {
		cout << "\nDeleting a node ...  ";
	    myList.displayNode(ptr);
		myList.deleteNode( ptr );
	}
	myList.displayList(myList.head);

	// insert
	name = "s2";
	id = 2;
	ptr = myList.initNode( name, id );
	myList.insertNode( ptr );
	cout << "\nInserting a node ...  ";
	myList.displayNode(ptr);
	myList.displayList(myList.head);

	// reverse
	cout << "\nReversing the list ...  \n";
	myList.reverse();
	myList.displayList(myList.head);

	// delete
	cout << "\nIn the end, deleting the list ...  \n";
	myList.deleteList(myList.head);
	myList.displayList(myList.head);
	return 0;
}


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Example 5A - Detecting Circular (Loop) Linked List
/* This code has the following */
/*
	1. Adding Nodes
	2. Function returning the size of the list
	3. Making the list circular (loop)
	4. Detecting circular list
	5. Recursive printing 
*/

#include <iostream>
using namespace std;

struct Node
{
	int data;
	Node * next;
};

Node *root = 0;

void addNode(int n)
{
	if(root==0) {
		root = new Node;
		root->data = n;
		root->next = 0;
		return;
	}
	Node *cur = root;
	while(cur) {
		if(cur->next == 0) {
			Node *ptr = new Node;
			ptr -> data = n;
			ptr -> next = 0;
			cur -> next = ptr;
			return;
		}
		cur = cur->next;
	}
}

void makeCircular()
{
	if(!root || !root->next) return;
	Node *cur = root;
	while(cur) {
		if(cur->next == 0) {
			cur->next = root;
			return;
		}
		cur = cur->next;
	}
}

int sizeOfList()
{
	Node *cur = root;
	int size = 0;
	while(cur) {
		size++;
		if(cur->next == 0) {
			return size; 
		}
		cur = cur->next;	
	}
	return size;
}

bool detectCircular() 
{
	// Assuming the list may not be circular

	if(!root || !root->next) return false;
	Node *ptr1 = root;
	Node *ptr2 = root;

	while(ptr1 && ptr2) {
		ptr1 = ptr1->next;
		ptr2 = ptr2->next;
		if(ptr2) {
		       ptr2 = ptr2->next;
		       if(!ptr2) return false;
		}
		else {
			return false;
		}
		cout << ptr1->data << "," << ptr2->data << endl;
		if(ptr1==ptr2) {
			return true;
		}
	}
	return false;
}

void printRecursive(Node *ptr)
{
	if(!ptr) {
		cout << endl;
		return;
	}
	cout << ptr->data << " ";
	printRecursive(ptr->next);
}

int main(int argc, char **argv)
{
	addNode(10);addNode(20);addNode(30);addNode(40);addNode(50);
	addNode(60);addNode(70);addNode(80);addNode(90);addNode(100);
	
	printRecursive(root);

	cout << "size of list = " << sizeOfList() << endl;
	 
	makeCircular();

	if(detectCircular()) cout <<"Circular\n";
	else cout << "Normal\n";
	 
}

Output from the run:

10 20 30 40 50 60 70 80 90 100
size of list = 10
20,30
30,50
40,70
50,90
60,10
70,30
80,50
90,70
100,90
10,10
Circular


Example 5B - Detecting Circular (Loop) Linked List (Generic Class with Template)
#include <iostream>
#include <string>

using namespace std;

template <class T>
class LinkedList
{
private:
	struct node
	{
		T data;
		node * next;
	} *head;

public:
	LinkedList();
	~LinkedList();
	void add(T d);
	void remove(T d);
	void clear();
	void makeCircular();
	bool isCircular();
	void display(const char* s);
};

template <class T>
LinkedList<T>::LinkedList()
{
	head = NULL;
}	

template <class T>
LinkedList<T>::~LinkedList()
{
	node *p, *q;
	p = head;
	if(p == NULL) return;
	while(p) {
		q = p->next;
		delete p;
		p = q;
	}
}

template <class T>
void LinkedList<T>::add(T d)
{	
	node *p, *q;
	if(head == NULL) {
		head = new node;
		head->data = d;
		head->next = NULL;
		return;
	} 
	p = head;
	while(p->next != NULL) 
		p = p->next;
	q = new node;
	q->data = d;
	q->next = NULL;
	p->next = q;	
}

template <class T>
void LinkedList<T>::remove(T d)
{
	node *p, *q;
	if(head == NULL) return;
	p = head;
	while(p) {
		if(p->data == d) {
			q->next = p->next;
			delete p;
			return;
		}
		q = p;
		p = p->next;
	}
}

template <class T>
void LinkedList<T>::clear()
{
	node *p, *q;
	if(head == NULL) return;
	p = head;
	while(p) {
		q = p->next;
		delete p;
		if(q != head)  {
			head = NULL;
			return;
		}
		p = q;
	}
}

template <class T>
void LinkedList<T>::makeCircular()
{
	node *p;
	if(head == NULL || head->next == NULL) return;
	p = head;
	while(p) {
		if(p->next == NULL) {
			p->next = head;
			return;
		}
		p = p->next;
	}
}

template <class T>
bool LinkedList<T>::isCircular()
{
	node *p, *pp;
	if(head == NULL || head->next == NULL) return false;
	p = head;
	pp = head;
	while(pp) {
		p = p->next;
		if(pp->next == NULL) return false;
		pp = (pp->next)->next;
		if(p == pp) return true;
	}
	return false;
}

template <class T>
void LinkedList<T>::display(const char* s)
{
	node *p;
	if(head == NULL) return;
	p = head;
	while(p) {
		if(s == "string") 
			cout << p->data << endl;
		else
			cout << p->data << ' ';
		p = p->next;
		if(p != NULL) {
			if(p == head) return;
		}
	}
	if(s == "integer") cout << endl;
}
 
int main()
{
	LinkedList<string> sList;
	sList.add("Wolfgang Amadeus Mozart");
	sList.add("Franz Peter Schubert");
	sList.add("Pyotr Ilyich Tchaikovsky");
	sList.add("Clude-Achille Debussy");
	sList.add("Camille Saint-Saens");
	sList.display("string");
	sList.clear();

	LinkedList<int> iList;
	iList.add(40);
	iList.add(50);
	iList.add(60);
	iList.add(70);
	iList.add(80);
	iList.add(90);
	iList.add(100);
	iList.add(10);
	iList.add(20);
	iList.add(30);
	iList.display("integer");

	/* link last element to the first */
	iList.makeCircular();

	if(iList.isCircular()) cout <<"This is circular list\n";
	iList.display("integer");

	iList.clear();
	cout << "\ndisplay after clear()\n";
	iList.display("integer");

	return 0;
}

Output from the run is:

Wolfgang Amadeus Mozart
Franz Peter Schubert
Pyotr Ilyich Tchaikovsky
Clude-Achille Debussy
Camille Saint-Saens
40 50 60 70 80 90 100 10 20 30
This is circular list
40 50 60 70 80 90 100 10 20 30
display after clear()




Your Ad Here


Example 6 - Stack Using Linked List

This stack is using linked list as its data structure.

/* Stack operations */

#include <iostream<

using namespace std;

typedef struct Element
{
	void *data;
	struct Element *next;
} Element;

bool push(Element **top, void *data)
{
	Element *elem = new Element;
	if(!elem) return false;

	elem->data = data;
	elem->next = *top;
	*top = elem;
	return true;
}

bool createStack(Element **top)
{
	*top = NULL;
	return true;
}

bool pop(Element **top, void **data )
{
	Element *elem;
	if( !(elem = *top) ) return false;

	*data = elem->data;
	*top = elem->next;
	delete elem;
	return true;
}

bool deleteStack(Element **top)
{
	Element *elem;
	while(*top) {
		elem = (*top)->next;
		delete *top;
		*top = elem;
	}
	return true;

}

void printStack(Element *top) 
{
	if(top==NULL) {
		cout << "Empty!" << endl;
	}
	Element *cur = top;
	while(cur) {
		cout << *(static_cast<int *>(cur->data)) << " ";
		cur = cur->next;
	}
	cout << endl << endl;
}

int main()
{
	Element *head;
	createStack(&head);
	int n1 = 10, n2 = 20, n3 = 30, n4 = 40, n5 = 50;
	push(&head, &n1);
	push(&head, &n2);
	push(&head, &n3);
	push(&head, &n4);
	push(&head, &n5);

	printStack(head);

	void * n;
	pop(&head, &n);
	cout << "popped " << *(static_cast<int*>(n)) << endl;
	pop(&head, &n);
	cout << "popped " << *(static_cast<int*>(n)) << endl;
	cout << endl;

	printStack(head);

	cout << "deleting stack..." << endl;
	deleteStack(&head);
	printStack(head);
}
stack_outputA



Example 7 - Stack Class Using Linked List

The code below is almost the same as the code in Example 6 except it's using Stack class.

#include <iostream>

using namespace std;

class Stack
{
public:
	Stack();
	~Stack();
	void push(void *data);
	void *pop();
	void print();
protected:
	typedef struct Element {
		struct Element *next;
		void *data;
	} Element;

	Element *top;
};

Stack::Stack() {
	top = NULL;
}

Stack::~Stack() {
	while(top) {
		Element *elm = top->next;
		delete top;
		top = elm;
	}
}

void Stack::push(void *data) {
	Element *elm = new Element;
	elm->data = data;
	elm->next = top;
	top = elm;
}

void *Stack::pop() {
	void *data;
	if(top == NULL) return data;
	data = top->data;
	Element *elm = top;
	top = elm->next;
	delete elm;
	return data;
}

void Stack::print() {
	Element *elm = top;
	while(elm) {
		cout << *(static_cast<int*>(elm->data)) << " " ;
		elm = elm->next;
	}
	cout << endl;
}

int main()
{
	Stack *st = new Stack;
	int n1 = 10;
	int n2 = 20;
	int n3 = 30;
	int n4 = 40;
	int n5 = 50;
	st->push(&n1);
	st->push(&n2);
	st->push(&n3);
	st->push(&n4);
	st->push(&n5);
	st->print();
	cout << *(static_cast<int*>(st->pop()))<< " poped\n";
	cout << *(static_cast<int*>(st->pop()))<< " poped\n";
	st->print();
	cout << endl;
}

stack_outputB






Example 8 - The simplest Queue Using Linked List
#include <stdio.h>
#include <stdlib.h>

struct node
{
	int data;
	node *next;
};
typedef struct node node_t;

node_t *head = NULL;

void push(int n)
{
	node_t *newNode = (node_t *)malloc(sizeof(node_t));
	newNode->data = n;
	newNode->next = NULL;

	if(head == NULL) {
		head = newNode;
		return;
	}

	node_t *cur = head;
	while(cur) {
		if(cur->next==NULL) {
			cur->next = newNode;
			return;
		}
		cur = cur->next;
	}
}

void pop()
{
	if(head==NULL) return;
	node_t *tmp = head;
	head = head->next;
	free(tmp);
}

void display()
{
	node_t *cur = head;
	while(cur) {
		printf("%3d",cur->data);
		cur = cur->next;
	}
	printf("\n");
}

int main()
{
	push(1);push(2);push(3);push(4);push(5);display();
	pop();display();
	pop();display();
	pop();display();
	pop();display();
	pop();display();
	return 0;
}

Output is:

  1  2  3  4  5
  2  3  4  5
  3  4  5
  4  5
  5







Example 9 - Finding Intersection and Union of Two Linked List

The following code finds intersection/union of two linked list and puts it into a new linked list.

#include <iostream>

using namespace std;

struct node 
{
	int data;
	node *next;
};

void add(struct node **head, int n)
{
	struct node *cur;
	struct node *new_node = (struct node *)malloc(sizeof(struct node));
	new_node->data = n;
	new_node->next = NULL;
	if(*head == NULL) {
		*head = new_node;
		return;
	}

	cur = *head;
	while(cur) {
		if(cur->next == NULL) {
			cur->next = new_node;
			return;
		}
		cur = cur->next;
	}
}

bool isDuplicate(struct node *head, int n)
{
	struct node* cur = head;
	while(cur) {
		if(cur->data == n) return true;
		cur = cur->next;
	}
	return false;

}

struct node *getIntersection(struct node *headA, struct node *headB)
{
	struct node *curA = headA;
	struct node *curB = headB;
	struct node *result = NULL;
	if(curA == NULL || curB == NULL) return NULL;
	while(curA) {
		while(curB) {
			if(curA->data == curB->data) {
				add(&result, curA->data);
			}
			curB = curB->next;
		}
		curB = headB;
		curA = curA->next;
	}
	return result;
}

struct node *getUnion(struct node *headA, struct node *headB)
{
	struct node *cur;
	struct node *result = NULL;
	if(headA == NULL && headB == NULL) return NULL;

	cur = headA;
	while(cur) {
		add(&result, cur->data);
		cur = cur->next;
	}

	cur = headB;
	while(cur) {
		/* check if the new data is already there */
		if(!isDuplicate(result, cur->data)) {
			add(&result, cur->data);
		}
		cur = cur->next;
	}
	return result;
}

void display(struct node *head)
{
	if(head == NULL) return;
	struct node *cur = head;
	while(cur) {
		cout << cur->data << ' ';
		cur = cur->next;
	}
	cout << endl;
}

int main()
{
	struct node *myListA = NULL;
	struct node *myListB = NULL;
	struct node *intersectionList = NULL;
	struct node *unionList = NULL;

	add(&myListA,10);
	add(&myListA,20);
	add(&myListA,30);
	add(&myListA,40);
	add(&myListA,50);
	add(&myListA,60);
	add(&myListA,70);
	cout << "List A: ";
	display(myListA);

	add(&myListB,10);
	add(&myListB,30);
	add(&myListB,50);
	add(&myListB,70);
	add(&myListB,90);
	add(&myListB,110);
	add(&myListB,130);
	cout << "List B: ";
	display(myListB);

	cout << "Intersection of A and B: ";
	intersectionList = getIntersection(myListA, myListB);
	display(intersectionList);

	cout << "Union of A and B: ";
	unionList = getUnion(myListA, myListB);
	display(unionList);

	return 0;
}

Output is:

List A: 10 20 30 40 50 60 70
List B: 10 30 50 70 90 110 130
Intersection of A and B: 10 30 50 70
Union of A and B: 10 20 30 40 50 60 70 90 110 130



Example 10 - Another Example of Generic Linked List

The following example is another example of generic use of linked list. It will be used as a base for doubly linked list later.

#include <iostream>

using namespace std;

template <typename T>
class List
{
	struct Node
	{
		T data;
		Node *next;
		Node(T d, Node *n = 0):data(d), next(n) {}
	};
	Node *head;

public:
	List(Node *h = 0):head(h){}
	~List();
	void insert(Node *loc, T d);
	void push_back(T d);
	void push_front(T d);
	T pop_back();
	T pop_front();
	void erase(Node *loc);
	void display();
	Node *search(T d);
};

// destructor
template <typename T>
List<T>::~List()
{
	Node *tmp;
	while(head) {
		tmp = head;
		head = head->next;
		delete tmp;
	}
}

// insert d before loc
template <typename T>
void List<T>::insert(Node *loc, T d) 
{ 
	Node *new_node = new Node(d,0);
	if(!head) {
		head = new_node;
		return;
	}
	if(loc == head) {
		push_front(d);
		return;
	}
	Node *cur = head;
	while(cur->next) {
		if(cur->next == loc) {
			new_node->next = cur->next;
			cur->next = new_node;
			return ;
		}
		cur = cur->next;
	}
}

template <typename T>
void List<T>::push_back(T d) 
{
	Node *new_node = new Node(d,0);
	if(!head) {
		head = new_node;
		return;
	}
	Node *cur = head;
	while(cur) {
		if(!cur->next) {
			cur->next = new_node;
			return;
		}
		cur = cur->next;
	}
}

template <typename T>
void List<T>::push_front(T d)
{
	Node *new_node = new Node(d,0);
	if(!head) {
		head = new_node;
		return;
	}
	new_node->next = head;
	head = new_node;
	return;
}

template <typename T>
T List<T>::pop_back() 
{
	Node *cur = head;
	while(cur) {
		if(!cur->next) {
			T data (cur->data);
			delete cur;
			head = NULL;
			return data;
		}
		else {
			if(!cur->next->next)  {
				T data (cur->next->data);
				cur->next = NULL;
				delete cur->next;
				return data;
			}
		}
		cur = cur->next;
	}
	return NULL;
}

template <typename T>
T List<T>::pop_front()
{
	if(!head) return NULL;
	Node *tmp = head;
	T data (head->data);
	if(head->next) {
		head = head->next;
		delete tmp;
		return data;
	}
	delete tmp;
	head = NULL;
	return data;
}

template <typename T>
void List<T>::erase(Node *loc)
{
	if(loc == head) {
		Node *tmp = head;
		head = head->next;
		delete tmp;
		return;
	}
	Node *cur = head;
	while(cur) {
		if(cur->next == loc) {
			cur->next = loc->next;
			delete loc;
		}
		cur = cur->next;
	}
}

template <typename T>
typename List<T>::Node* List<T>::search(T d)
{
	if(!head) return NULL;
	Node* cur = head;
	while(cur) {
		if(cur->data == d) return cur;
		cur = cur->next;
	}
	return NULL;
}

template <typename T>
void List<T>::display()
{
	if(!head) return;
	Node *cur  = head;
	while(cur) {
		cout << cur->data << " " << endl;
		cur = cur->next;
	}
	cout << endl;
}

int main()
{
	List<int> *myList = new List<int>(NULL);

	cout << "push_back() 20, 30 40, 50\n\n";
	myList->push_back(20);
	myList->push_back(30);
	myList->push_back(40);
	myList->push_back(50);
	myList->display();

	cout << "push_front() 10\n\n";
	myList->push_front(10);
	myList->display();

	cout << "erase 30\n\n";
	myList->erase(myList->search(30));
	myList->display();

	cout << "insert 30 before 40\n\n";
	myList->insert(myList->search(40),30);
	myList->display();

	cout << "pop_back()\n";
	cout << myList->pop_back() << " just back popped\n\n";
	myList->display();

	cout << "pop_front()\n";
	cout << myList->pop_front() << " just front popped\n\n";
	myList->display();

	return 0;
}


generic linked list





List of Linked List Examples of This Page
  • Example 1
    When the head of the list is not a global pointer.
  • Example 2 and Example 3
    When the head of the list is a global pointer.
    There are some implementation differences between these two examples.
  • Example 4
    Used class & structure in that class.
  • Example 5A
    Detecting circular (loop) linked list.
  • Example 5B
    Detecting circular (loop) linked list (Generic Class with Template).
  • Example 6
    Stack with linked list data structure.
  • Example 7
    Class Stack with linked list data structure.
  • Example 8
    Queue with linked list data structure.
  • Example 9
    Finding intersection and union of two linked lists.
  • Example 10
    Generic linked lists.

Also, there is another set of linked list quiz.








Jiri_PiaGol





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